Lenses and Systems of Lenses |
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Page 53
... 88. We will now suppose that the source of light is at a point X on the axis of the system , and we will denote by u its reduced distance from the vertex of the refracting surface REFRACTION AT ANY NUMBER OF SURFACES . 53.
... 88. We will now suppose that the source of light is at a point X on the axis of the system , and we will denote by u its reduced distance from the vertex of the refracting surface REFRACTION AT ANY NUMBER OF SURFACES . 53.
Page 54
... suppose that there are n surfaces , we have for the last pair of distances 27 V- + t , and v . 1-1 We will suppose the radii of curvature of the surfaces to be r1 , " " , ... , successively ; and the indices of refraction of the ...
... suppose that there are n surfaces , we have for the last pair of distances 27 V- + t , and v . 1-1 We will suppose the radii of curvature of the surfaces to be r1 , " " , ... , successively ; and the indices of refraction of the ...
Page 58
... 4-3-42-4 2n - 2 = = 0 , = 0 , A2n - 3 - P242n - 4 - A2n − 5 = 0 , ....... & c . , of which the last are ...... A - 4 -4 , - A1 = 0 , 4 , - P141 = 1 . 97. If , for example , we suppose that there 58 LENSES AND SYSTEMS OF LENSES .
... 4-3-42-4 2n - 2 = = 0 , = 0 , A2n - 3 - P242n - 4 - A2n − 5 = 0 , ....... & c . , of which the last are ...... A - 4 -4 , - A1 = 0 , 4 , - P141 = 1 . 97. If , for example , we suppose that there 58 LENSES AND SYSTEMS OF LENSES .
Page 59
Charles Pendlebury. 97. If , for example , we suppose that there are four surfaces , we have 2n - 1 = 7 , and we get A , -P , 4- A A - t4- A -- 4 - A - 4 - A , = 0 = 0 0 ... suppose that there are REFRACTION AT ANY NUMBER OF SURFACES . 59.
Charles Pendlebury. 97. If , for example , we suppose that there are four surfaces , we have 2n - 1 = 7 , and we get A , -P , 4- A A - t4- A -- 4 - A - 4 - A , = 0 = 0 0 ... suppose that there are REFRACTION AT ANY NUMBER OF SURFACES . 59.
Page 60
Charles Pendlebury. 98. If , again , we suppose that there are two refracting surfaces , we have 2n − 1 = 3 , and therefore therefore - - a ̧ — μ‚a‚— A1 = 0 A12 - t , A1 = 1 ; A1 = P2 A1 = - | - P1 , -1 , 여 0 1 , - - t1 1 0 , 1 , - Pa ...
Charles Pendlebury. 98. If , again , we suppose that there are two refracting surfaces , we have 2n − 1 = 3 , and therefore therefore - - a ̧ — μ‚a‚— A1 = 0 A12 - t , A1 = 1 ; A1 = P2 A1 = - | - P1 , -1 , 여 0 1 , - - t1 1 0 , 1 , - Pa ...
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Common terms and phrases
2nd edition 3rd edition 4th edition absolute distances Aeneid axis Book Camb Cambridge Carl Neumann conjugate planes conjugate points continued fraction Demy 8vo denote determine deviation Elementary emergent ray equations equivalent lens extreme media F and F F. A. PALEY Fcap Fellow of St focal length formula French Geometry GEORGE LONG Grammar Greek Hence incident ray Index infinite distance J. H. FREESE John's College Latin LL.D luminous point M.A. Small post m₁ magnification produced Math meet the axis numerous P₁ P₂ parallel PENDLEBURY PH.D point conjugate point Q position Principal Planes Principal Points Professor Prose reduced distance refracted ray refracting surface refractive indices respectively revised School second surface sewed Small post 8vo straight lines system of lenses t₁ Texts with Notes thick lens thin lens Translated Trinity College V₁ vertex vols μη μο Мо
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