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Height

Length Height Length Height Length of Arc. of Arc. of Arc. of Arc. of Arc. of Arc.

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.928 2.29270 947 2.32785 || 9652-36191
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.983 2.39631

·966 2.36381

•984 2.39823

.967 2.36571

•985 2.40016

.968 2.36762

.986 2.40208

•929 2.29453 | 948 2-32972

•930 2.29636·949 2.33160
•931 | 2.29820 || ·950 | 2·33348
•932 2.30004 951 2.33537 •969 2.36952
933 2.30188 952 2.33726 || ·970 | 2·37143
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934 2.30373 || 9532-33915 || ·971 | 2·37334

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.993 2.41556

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.995 2.41943

•996 2.42136

-997 2.42329 .9982-42522

.981 2.39247 •999 2.42715

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To find the Length of an Arc of a Circle, or the Curve of a Right Semi-Ellipse.

RULE.-Divide the height by the base, and the quotient will be the height of an arc of which the base is unity. Seek, in the Table of Circular or Semi-elliptical arcs, as the case may be, for a number corresponding to this quotient, and take the length of the arc from the next right-hand column. Multiply the number thus taken out by the base of the arc, and the product will be the length of the arc or curve required.

EXAMPLE 1.—In Southwark Bridge, London, the profiles of the arches are the arcs of circles; the

span of the middle arch is 240 feet, and the height 24 feet; required the length of the arc.

24240100; and 100, as per Table V., is

1.02645.

=

Hence 1.02645 x 240 246-34800 feet, the length required.

EXAMPLE 2.-The profiles of the arches of Waterloo Bridge are all equal and similar semi-ellipses; the span of each is 120 feet, and the rise 28 feet; required the length of the curve.

28120233; and 233, as per Table VI., is

1.19040.

Hence 1.19010 x 120 = 142-81200 feet, the length required.

In this example there is, in the division of 28 by 120, a remainder of 40, or one-third part of the divisor; consequently the answer, 142.81200, is rather less than the truth. But this difference, in even so large an arch, is little more than half an inch; therefore, except where extreme accuracy is required, it is not worth computing.

These Tables are equally useful in estimating works which may be carried into practice, and the quantity of work to be executed from drawings to a scale.

As the Tables do not afford the means of finding the lengths of the curves of elliptic arcs which are

less than half of the entire figure, the following geometrical method is given to supply the defect.

Let the curve, of which the length is required to be found, be A B C.

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Produce the height line, B d, to meet the centre of the curve, in g. Draw the right line, A g, and from the centre, g, with the distance, g B, describe an arc, Bh, meeting Ag in h. Bisect A h in i, and from the centre, g, with the radius, g i, describe the arc ik, meeting d B, produced to k; then ik is half the arc A B C.

6*

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