Norris's Hand-book for Locomotive Engineers and Machinists ... |
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Page 19
... EXAMPLE . - Required the number of imperial gallons in 4743 old wine gallons : — 40003332 700 583.2 40 33.32 3 = 2.490 3951-019 imperial gallons . TROY WEIGHT . AVOIRDUPOIS WEIGHT . AVOIRDUPOIS WEIGHT . Dec. WEIGHTS AND MEASURES . 19.
... EXAMPLE . - Required the number of imperial gallons in 4743 old wine gallons : — 40003332 700 583.2 40 33.32 3 = 2.490 3951-019 imperial gallons . TROY WEIGHT . AVOIRDUPOIS WEIGHT . AVOIRDUPOIS WEIGHT . Dec. WEIGHTS AND MEASURES . 19.
Page 52
... EXAMPLE . - Required the area of a segment of a circle , whose height is 31 feet , and the diameter of the circle 50 feet . 311 3.25 ; and 3.25 ÷ 50 · 065 . 065 , as per Table , 021659 ; and 021659 × 502 54.147500 , the area required ...
... EXAMPLE . - Required the area of a segment of a circle , whose height is 31 feet , and the diameter of the circle 50 feet . 311 3.25 ; and 3.25 ÷ 50 · 065 . 065 , as per Table , 021659 ; and 021659 × 502 54.147500 , the area required ...
Page 53
... EXAMPLE . - Required the area of a zone whose longest chord is 50 , and height 15 . 15 ÷ 50 = 300 ; and 300 , as per Table , = · 280876 . Hence · 280876 × 502 = 702.19 , the area of the zone . RULE 2. - When the zone is greater than a ...
... EXAMPLE . - Required the area of a zone whose longest chord is 50 , and height 15 . 15 ÷ 50 = 300 ; and 300 , as per Table , = · 280876 . Hence · 280876 × 502 = 702.19 , the area of the zone . RULE 2. - When the zone is greater than a ...
Page 54
... EXAMPLE . - Required the area of the segment of a circle , the chord being 12 , and the versed sine 2 . 24 12 x 2 = 24 ; 8 ; and 8 × 2 = 16 . 3 23 24 ( 12 x 2 ) Hence 163333 segment very nearly . × = · 3333 . 16.3333 , the area of the ...
... EXAMPLE . - Required the area of the segment of a circle , the chord being 12 , and the versed sine 2 . 24 12 x 2 = 24 ; 8 ; and 8 × 2 = 16 . 3 23 24 ( 12 x 2 ) Hence 163333 segment very nearly . × = · 3333 . 16.3333 , the area of the ...
Page 63
... be the length of the arc or curve required . EXAMPLE 1. — In Southwark Bridge , London , the profiles of the arches are the arcs of circles ; the span of the middle arch is 240 feet , and RULES FOR FINDING THE LENGTHS OF ARCS . 63.
... be the length of the arc or curve required . EXAMPLE 1. — In Southwark Bridge , London , the profiles of the arches are the arcs of circles ; the span of the middle arch is 240 feet , and RULES FOR FINDING THE LENGTHS OF ARCS . 63.
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Common terms and phrases
abscissa Atmospheric Railway avoirdupois axle blast-pipe boiler brass centre circle circular segments Circum circumference cloth coke conjugate connecting-rod copper crank Cube Root cubic feet cubic foot cubic inch curve cylinder cylinder in inches Dauphiny Decimal or Reciprocal diame diameter distance driving wheels eccentric-rod equal EXAMPLE.-Required find the Area find the Solidity fire-box Fraction or Numb friction Frustum fulcrum fulcrum and valve Gallons gauge give the solidity Height Length horses Hyperbola iron Length of Arc leverage locomotive engine metallic mile morocco motion multiply the sum North Shields ordinate Ounces Parabola pipes piston piston-rod plates Pounds pressure quotient radius rails Railway resistance revolving axis RULE RULE.-Multiply RULE.-To find screw segment shaft side smoke-box spindle square inch Square Root steam stroke subtract thickness throw tion tons trapezium tubes valve velocity Volume whole weight yards Zone